Question

Length and breadth of 3 rectangle given below


a. 10m and 6m also find one has greater perimeter one has least area

Answer 1

Answer:

Explanation:

perimeter of first rectangle

2(l+b)

2(10+6)

20+12

=32m

perimeter of second rectangle

2(l+b)

2(20+10)

40+20

=60m

perimeter of third rectangle

2(l+b)

2(15+5)

30+10

=40m

from above rectangle no.2 have largest perimeter

area of first rectangle

=l×b

=10×6

=60 sq.m

area of second rectangle

=l×b

=20×10

=200 sq.m

area of third rectangle

=l×b

=15×5

=75 sq.m

from above

rectangle no.1 have least area

hey mate hope the answer will help you☺☺☺☺☺☺☺☺☺☺☺☺☺☺