Math, asked by nitin3263, 10 months ago

length and breadth of a rectangle are equal. if perimeter of rectangle is 64cm, then find its area.​

Answers

Answered by StarGazer001
18
\boxed{Answer\:=>\:256cm^2}

\bold{Given\:,}

\bold{Length\:and\:breadth\:of\:the\:rectangle\:are\:equal\:.}

\bold{Let\:length\:of\:the\:rectangle\:be\:'x'\:}

\bold{Let\:breadth\:of\:the\:rectangle\:be\:'x'\:}

\bold{Perimeter\:of\:the\:rectangle\:=\:64cm}

\bold{Perimeter\:of\:the\:rectangle\:=\:2(l+b)}

\bold{64\:=\:2(x+x)}

\bold{64\:=\:2x+2x}

\bold{64\:=\:4x}

\bold{64\div4\:=\:x}

\bold{16\:=\:x}

\underline{Value\:of\:x\:=16}

\bold{Therefore\:,}

\bold{Length\:of\:the\:rectangle\:=\:16cm\:}

\bold{Breadthth\:of\:the\:rectangle\:=\:16cm\:}

\bold{Area\:of\:the\:rectangle\:=\:l\times b}

\bold{Area\:of\:the\:rectangle\:=\:16\times16}

\bold{Area\:of\:the\:rectangle\:=\:256cm^2}

\underline{Therefore\:area\:of\:the\:rectangle\:=\:256cm^2}
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