Math, asked by vaishvaishnav797, 4 months ago

Length and breadth of a rectangle arebin the ratio 5:3 If it's perimeter is 840 m, what is the area of the rectangle

Answers

Answered by Anonymous
6

Given :

Length and breadth of rectangle = 5 : 3

Perimeter of rectangle = 840m

To find :

Area of the rectangle.

Solution :

Here,

Length = 5x

Length = 5xBreadth = 3x

Using the formula Perimeter = 2(l+b)

 \bf \implies 2(L  +  B) = 840 \\  \\ \bf \implies2(5x + 3x) = 840\\  \\ \bf \implies 2(8x) = 840 \\  \\ \bf \implies 16x = 840 \\  \\ \bf \implies x =  \dfrac{840}{16}  \\  \\ \bf \implies  \boxed{ \bf x = 52.5}

Thus, x = 52.5

So, length and breadth are :-

  • 5x = 5 × 52.5 = 262.5
  • 3x = 3 × 52.5 = 157.5

Hence, Length = 262.5m and breadth = 157.5m.

Now, Area :

 \implies \boxed{\bf Area = L \times B} \\ \\ \bf \implies 262.5 \times 157.5 \\ \\ \bf \implies  41,343.75

Therefore, Area of the rectangle is 41,343.75m².

\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}

Similar questions