Question

length and breadth of a rectangular garden is 12/5 and 3/2 find the area and perimeter of garden​

Answer 1

The length of rectangular garden is $\frac{12}{5}$ units and the breadth of rectangular garden is $\frac{3}{2}$ units.

We know that, the area of rectangle of length $l$ and breadth $b$ is given by,

$\boxed{\bf{Area_{(rectangle)} = l \times b}}$

By substituting the known values in the formula, we get:

$\implies Area_{(rectangle)} = \dfrac{12}{5} \times \dfrac{3}{2} \\ \\ \implies Area_{(rectangle)} = \dfrac{6}{5} \times 3 \\ \\ \implies \boxed{\bf{Area_{(rectangle)} = \dfrac{18}{5}}}$

Now we know that, the perimeter of rectangle of length $l$ and breadth $b$ is given by,

$\boxed{\bf{Perimeter_{(rectangle)} = 2(l + b)}}$

By substituting the known values in the formula, we get:

$\implies Perimeter_{(rectangle)} = 2\left(\dfrac{12}{5} + \dfrac{3}{2}\right) \\ \\ \implies Perimeter_{(rectangle)} = 2\left(\dfrac{24 + 15}{10}\right) \\ \\ \implies Perimeter_{(rectangle)} = 2 \times \dfrac{39}{10} \\ \\ \implies \boxed{\bf{Perimeter_{(rectangle)} = \dfrac{39}{5}}}$

Hence, the area of rectangular garden is 18/5 sq. units and the perimeter of rectangular garden is 39/5 units.

Answer 2

Step-by-step explanation:

We know that,

• Length = $\sf{\dfrac{12}{5}}$
• Breadth = $\sf{\dfrac{3}{2}}$

Area of a Rectangle :-

Length $(l)$ × Breadth $(b)$

Substituting values in Formula,

$\sf⟹{\dfrac{12}{5}}\:×\:{\dfrac{3}{2}}$

$\sf⟹{\dfrac{6\:×\:3}{5}}$

$\sf⟹{\dfrac{18}{5}}$

Perimeter of a Rectangle :-

2 [Length $(l)$ + Breadth $(b)$]

Substituting values in Formula,

$\sf⟹$ $\sf2({\dfrac{12}{5}}\:+\:{\dfrac{3}{2}}$)

$\sf⟹$ $\sf2({\dfrac{24\:+\:15}{10}}$)

$\sf⟹$ $\sf2({\dfrac{39}{10}}$)

$\sf⟹$$\sf{\dfrac{39}{5}}$

Hence, Area of the rectangular Garden is 18/5 sq.units and Perimeter is 39/2 sq. units.