Length and breadth of front page of a magazine is 30cm and 22cm respectively find the area of the front page
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Answered by
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Given conditions ⇒
Length = 30 cm.
Breadth = 22 cm.
∵ Area of the Rectangle = Length × Breadth.
∴ Area = 30 × 22
⇒ Area of the Rectangle = 660 cm².
Hence, the Area of the Front page which is in the shape of the Rectangle is 660 cm².
Hope it helps.
Atharvaedits:
nic answer sir/madam
Answered by
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Area or more specifically surface area in this case is defined as the product of the length and breadth of the object in case of 2D ( 2 - Dimensional ) shapes like square, rectangle, triangle, rhombus, parallelogram, trapezium, etc.
Here in this question we are provided with the following data:
Length of the front page, l = 30 cm
Breadth ( Width ) of the front page, b = 22 cm
As mentioned or discussed earlier,
Area of the front page of the magazine, A = Length * Breadth ( Width )
A = l * b
A = 30 * 22 square centimetres
A = 660 sq. cm
A = 660 cm^2
Therefore,
Area of the front page of the magazine will measure to 660 sq. cm or 660 cm^2.
Here in this question we are provided with the following data:
Length of the front page, l = 30 cm
Breadth ( Width ) of the front page, b = 22 cm
As mentioned or discussed earlier,
Area of the front page of the magazine, A = Length * Breadth ( Width )
A = l * b
A = 30 * 22 square centimetres
A = 660 sq. cm
A = 660 cm^2
Therefore,
Area of the front page of the magazine will measure to 660 sq. cm or 660 cm^2.
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