Question

length and width of the rectangle are consecutive odd integers and the perimeter is 168 cm. Find the length and width of the rectangle

Please please give me set to set explanation

Answer 1

Answer:

l=41,b=43

Step-by-step explanation:

let l=x,

b=x+2

perimeter=2(l+b)

168=2[x+(x+2)]

=2(2x+2)

168=4x+4

164÷4=x

x=41

l=41

b=x+2=43

Answer 2

Answer:

Step-by-step explanation:

Let the consecutive odd no.s be x and x+2.

2(l+b)=perimeter

2(x+x+2x)=168

2(4x)=168

8x=168

x=168/8

x=21

Therefore,the width =21cm

The length=x+2=23cm

Hope this is correct and it helps you.