Question

length breadth and height of a room are 8m,6m,and 4m respectively.find the diagonal of the room and the area of the four walls of the room.

Answer 1

diagonal of room =√l²+b²+h²
=√8²+6²+4²
=√64+36+16
=10.77

area of four wall = 2(l+b)*h
=2(8+6)*4
=112m. @

Answer 2

$\Large{\textbf{\underline{\underline{According\:to\:the\:Question}}}}$

Length of Cuboid = 8 (l)

Breadth of Cuboid = 6 (b)

Height of Cuboid = 4 (h)

Now,

${\boxed{\sf\:{Volume\;of\;Cuboid=l\times b\times h}}}$

= 8 × 6 × 4

= 192 m³

Also,

Total Surface area of Cuboid = 2(lb + bh + hl)

= 2(8 × 6 + 6 × 4 + 8 × 4)

= 2(48 + 24 + 32)

= 2 × 104

= 208 m²

${\boxed{\sf\:{Diagonal\;of\;Cuboid=\sqrt{l^2+b^2+h^2}}}}$

= √(8² + 6² + 4²)

= √(64 + 36 + 16)

= √116

= 10.77 m

Now,

Area of four walls of cuboid = 2(l + b)h

= 2(8 + 6) × 4

= 2 × 14 × 4

= 112 m²