Question

Length: breadth and height of an open container from outside is 1.5m, 1m
and 25m respectively, which is made by iron sheet of 3em thick. Find the
capacity of the container and volume of iron used.​

Answer 1

FINAL ANSWER:

capacity of the container is 37.5 $m^{3}$

volume of iron used is 1.477999 $m^{3}$

GIVEN:

Length = l2 = 1.5m

breadth = b2 = 1m

height = h2 = 25m

thickness of sheet = 0.03 m

to find volume of container subtract 0.03 m from each

so after adding we get

Length = l1 = 1.53 m

breadth =b1 = 1.03 m

height =c1 = 25.03 m

TO FIND:

• the  capacity of the container

• volume of iron used.​

FORMULA USED:

V=L×b×h

SOLUTION:

∴ volume of capacity of container =

V2=l2×b2×b3

V2=1.5×1×25

V2=37.5 $m^{3}$

and,

V1=l1×b1×c1

V1=1.53×1.03×25.03

V1=39.444777 $m^{3}$

∴ volume of iron used in making of container = V1 - V2

                                                                            = 39.444777 - 37.5

                                                                            = 1.477999 $m^{3}$

--------------------------------------------------------------------------------------------------------------

hope this answerer is helpful  

if you like the answer than please mark me as a brainliest  

this is anvaya signing out  

peace