Length diagonals of rhombus are in ratio 6:8 if it's perimeter is 40 cm. Find the length of the shorter diagonal
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As we know that the perimeter of rhombus = 4*side
40 = 4*side
40/4 = side
10 = side
Now,
by pythagoras theorem,
(6x/2)^2 +(8x/2)^2 = 10^2
9x^2 +16x^2 = 100
25x^2 = 100
x^2 = 100/25
x^2= 4
x= 2
Now,
length of diagonals is
6*2 = 12cm
and
8*2 = 16cm
i hope this will help you
-by ABHAY
40 = 4*side
40/4 = side
10 = side
Now,
by pythagoras theorem,
(6x/2)^2 +(8x/2)^2 = 10^2
9x^2 +16x^2 = 100
25x^2 = 100
x^2 = 100/25
x^2= 4
x= 2
Now,
length of diagonals is
6*2 = 12cm
and
8*2 = 16cm
i hope this will help you
-by ABHAY
AKMCHA545:
THANKS
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