Question

Length is 39/2 and breadth is 122/3 .find the perimet

Answer 1

Length=

$\frac{39}{2 }$

Breadth=

$\frac{122}{ 3}$

Pereter of rectangle=2(L+B)

=2(39/2+122/3)

=2 *60.1666666667

=120.333333333