Question

length of 1st digonal is 4/3 times of other if area is 96 cm square find the height of rhombus

Answer 1

Heya Frnd ..............☺

$Ar. \: of \: rhombus \: = \: \frac{d1 \times d2}{2}$

=> 96 = x × 4/3x

=> 96 × 3 /4 = x²

=> x = √72

NOW,

Diagonals of rhombus are _|_ bisectors.

So,

By PGT , ......,( SEE THE PIC)

Base = √50

Height (h) = ?

So,

Ar. of rhombus = Ar. of ||gm

= b × h

=> 96 = √50 × h

=> 96/√50 = h

=> $\boxed{13.6 cm = h}.$.........★ANS★

_________☺☺☺__________

HOPE IT WILL HELP U................✔