length of a chord of a circle with radius 5 cm is 8 cm if O is a chord a b is a chord than OD perpendicular to a b then find OD
Vedant250204:
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Answers
Answered by
7
The answer is. .....
r=5cm
length of chord=8cm
8/2 is half of chord =4cm
So,we apply pythagorous theorem......
In triangle...
perpendicular ^2=5^2-4^2
then,p^2=25-16
then,p=3
ANSWER
r=5cm
length of chord=8cm
8/2 is half of chord =4cm
So,we apply pythagorous theorem......
In triangle...
perpendicular ^2=5^2-4^2
then,p^2=25-16
then,p=3
ANSWER
Answered by
2
the answer is 3 CM by applying Pythagoras theorem
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