Question

length of a diagonal AC and BD of a rhombus are 3 cm and 4 cm respectively then perimeter of rhombus are​

Answer 1

Bro the below answer is correct so the below answer

Answer 2

Answer:

the perimeter of Rhombus is 14 cm.

Step-by-step explanation:

Since diagonals of rhombus ABCD divides the rhombus into 4 parts, let's take ∆AOB from rhombus (O is the point of intersection of diagonal AC and BD).

⇒ Area of Rhombus = 1/2(d1 * d2)

                                  = 1/2(3*4)

                                  = 1/2(12)

So, the area of Rhombus is 6 cm².

Side of Rhombus = √(d1)²+(d2)²/2

                             = √(3)²+(4)²/2

                            = √9+16/2

                            = 3+4/2

                            = 7/2

                            = 3.5 cm

Now, Perimeter of Rhombus = 4 (side)

                                                = 4 (3.5)

                                                = 14 cm

Hence, the perimeter of Rhombus is 14 cm.

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