Question

Length of a mi ute hand of a clock is 20cm.find the average velocity of the tip of minute's hand between 10am to 10:30pm

Answer 1

2TTr = 2 × 22/7 × 20 = 22 × 40 /7 = 880/7..... (CIRCUMFERENCE OF THE CIRCLE COMPLETED BY MINUTE HAND)

now,
360/880/7 = 360 × 7/ 880 = 2.86 or 2.9°(approx.)

now ,
10:30 - 10:0 = 30 mins

so,
2.9 × 30 / 60 .... ( dist. / time { in degrees / sec})
= 87 / 60
= 1.45°/sec. .....#Ans#

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