Question

Length of a minute hand of a clock is 4.5 cm. Find the average velocity of the tip of minute's hand between 6 AM to 6.30 P.M.​

Answer 1

Answer:

Given that,

Time t=30 min=1800 sec

Now, the length of the minute hand is almost as long as the radius of the clock

The displacement is

D=2×4.5

D=9cm

D=0.09m

Now, the velocity is

v=

t

D

v=

1800

0.09

v=5×10

−5

m/s

Hence, the average velocity is 5×10

−5

m/s

Displacement during 6:00 AM to 6:30 PM will be:

D=4.5×2=9cm

D=0.09 m

Time taken:

t=12.5 Hours.

t=12.5×3600 sec

Therefore,

Velocity will be given by:

v=

12.5×3600

0.09

=2×10

−6

m/s