Question

Length of a rectangle exceeds its breadth by 4 m. If the perimeter of the rectangle is 84 m,
find its length and breadth​

Answer 1

Step-by-step explanation:

Let the rectangle is of following measure

$breath = b \\ length = b + 4 \\ also \\ perimeter \: of \: rectangle = 2 \times( l + b) \\ and \: according \: to \: the \: question\\ perimeter \: of rectangle \: is \: 84 \:cm \\ so \\ 2 \times (l + b) = 84 \\ we \: konw \: that \: (l = b + 4 \: and \: b = b) \\ by \: putting \: values \\ 2 \times (b + 4 + b) = 84 \\ by \: transposing \: 2 \: to \: other \: side we \: will \: get\\ (b + 4 + b) = 84 \div 2 = 42\\ then \\ (2 b+ 4) = 42 \\ by \: transposing \: 4 \: we \: will \: get \\ (2b) = 42 - 4 = 38 \\ now \: transposing \: 2 \: to \: other \: side \: we \: will \: get \\ (b) = 38 \div 2 = 19 \\ so \: breadth = 19cm \\ we \: know \: that \: length \: is \: cm \: greater \: than \: breadth \: so \\ length = 19 + 4 = 23cm \: \\ breadth = 19cm \: and \: length = 23cm$

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