length of a rectangle exceeds its breadth by 4m.If the perimeter of the rectangle is 84m,find its length and breadth
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Answer:
let the breadth be x
then length be (x+4)
perimeter =2 (l+b)
84 = 2 (x+4+x)
84÷2 = x+4+x
42 = 2x+4
42-4 = 2x
38 = 2x
38÷2 = x
x = 19 m
length = x+4
= 19+4
=23m
breadth = 19m
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Answered by
0
Answer:
l= 23m and b= 19m.
Step-by-step explanation:
Given, l-b=4m, where l and b are the length and breadth of the rectangle respectively. So, l= 4+b.......(i). And perimeter of rectangle= 84m.
Since, Perimeter of rectangle= 2(l+b).
84= 2(4+b+b).
84/2= 2b+4.
42-4 = 2b.
b= 38/2= 19m.
Now, putting this value of b in (i):-
since, l= b+4.
so, l= 19+4.
or, l= 23m.
So, l= 23m and b= 19m.
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