length of a rectangle exceeds its breadth by 6cm .if the perimeter of the rectangle is 96cm. find its length and breadth in cm
Answers
Answered by
17
let breadth be x
then length be 6+x
perimeter of rectangle=2(l+b)
96=2(6+x+x)
92=12+4x
80=4x
20=x
lenght =20
and breadth =26
then length be 6+x
perimeter of rectangle=2(l+b)
96=2(6+x+x)
92=12+4x
80=4x
20=x
lenght =20
and breadth =26
Answered by
6
Answer:
length of rectangle is 27 cm and breadth is 21 cm.
Step-by-step explanation:
Let x be the length and y be breadth of the triangle.
It has been given that length of a rectangle exceeds its breadth by 6cm. Thus, we have
x = y +6 ....(i)
Now, the perimeter of the triangle is given by
P = 2x + 2y
Substituting the value of x and the perimeter
96 = 2(y+6) + 2y
96 = 2y + 12 + 2y
4y = 96 - 12
4y = 84
y = 21
From equation (i)
x = 21 + 6
x = 27
Therefore, length of rectangle is 27 cm and breadth is 21 cm.
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