length of a rectangle is 10 cm and width 8 cm if its length and width are double what would be the area of the new rectangle How many times the area of the original is the area of the new rectangle ?
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Hey mate!
Here is your answer > >
Length of a rectangle=10 cm
Breadth of a rectangle=8 cm
Area of a rectangle=L×B=10×8=80 cm^2
●●●●●●●●●●●●●●●●●●●●●●●●●●●●●
Now,New length of rectangle=2×10=20 cm
New breadth of rectangle = 2×8=16 cm
New Area of rectangle = L×B=20×16=320 cm^2
●●●●●●●●●●●●●●●●●●●●●●●●●●●●●
Difference between both the areas=320-80=240 cm^2
The area of new rectangle is 4 times the area of original rectangle.
Hope it helps!
Thankyou ☆ ☆
#bebrainly
Here is your answer > >
Length of a rectangle=10 cm
Breadth of a rectangle=8 cm
Area of a rectangle=L×B=10×8=80 cm^2
●●●●●●●●●●●●●●●●●●●●●●●●●●●●●
Now,New length of rectangle=2×10=20 cm
New breadth of rectangle = 2×8=16 cm
New Area of rectangle = L×B=20×16=320 cm^2
●●●●●●●●●●●●●●●●●●●●●●●●●●●●●
Difference between both the areas=320-80=240 cm^2
The area of new rectangle is 4 times the area of original rectangle.
Hope it helps!
Thankyou ☆ ☆
#bebrainly
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