length of a rectangle is 12 cm and width 10 cm .If its length and width are doubled, what would be tge area of new rectangle? how many times the area of original rectangle is the area of the new rectangle?
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☆Hello friend☆
Initial Area = length×breadth
If dimensions increased by 2
New Area= 2length×2breadth
New Area=4 × Initial Area
Initial Area= 12×10cm
=120cm^2
New Area= (2×12)cm×(2×10)cm
=24cm×20cm
=480cm^2
Area increased= 480cm^2/120cm^2
= 4 times
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Initial Area = length×breadth
If dimensions increased by 2
New Area= 2length×2breadth
New Area=4 × Initial Area
Initial Area= 12×10cm
=120cm^2
New Area= (2×12)cm×(2×10)cm
=24cm×20cm
=480cm^2
Area increased= 480cm^2/120cm^2
= 4 times
Plz mark its as brainliest if u like it☺
Answered by
1
hii!!
here's ur answer...
given length of the rectangle is 12cm and breadth (width) is 10cm.
area of the rectangle = l×b
= 12×10
= 120cm²
if both the length and breadth of the rectangle is doubled, then the new length of the rectangle will be = 12×2 = 24cm
new breadth will be = 10×2 = 20cm
area of the new rectangle = l×b
= 24×20
= 480cm²
no. of times area of the New rectangle is more than original rectangle = 480/120
= 4
hence 4 times the area of new rectangle is more than the area of the original rectangle.
hope this helps..!
here's ur answer...
given length of the rectangle is 12cm and breadth (width) is 10cm.
area of the rectangle = l×b
= 12×10
= 120cm²
if both the length and breadth of the rectangle is doubled, then the new length of the rectangle will be = 12×2 = 24cm
new breadth will be = 10×2 = 20cm
area of the new rectangle = l×b
= 24×20
= 480cm²
no. of times area of the New rectangle is more than original rectangle = 480/120
= 4
hence 4 times the area of new rectangle is more than the area of the original rectangle.
hope this helps..!
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