Question

length of a rectangle is 12 cm and width 10 cm .If its length and width are doubled, what would be tge area of new rectangle? how many times the area of original rectangle is the area of the new rectangle?

Answer 1

☆Hello friend☆

Initial Area = length×breadth
If dimensions increased by 2
New Area= 2length×2breadth
New Area=4 × Initial Area

Initial Area= 12×10cm
=120cm^2
New Area= (2×12)cm×(2×10)cm
=24cm×20cm
=480cm^2
Area increased= 480cm^2/120cm^2
= 4 times

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Answer 2

hii!!

here's ur answer...

given length of the rectangle is 12cm and breadth (width) is 10cm.

area of the rectangle = l×b

= 12×10

= 120cm²

if both the length and breadth of the rectangle is doubled, then the new length of the rectangle will be = 12×2 = 24cm

new breadth will be = 10×2 = 20cm

area of the new rectangle = l×b

= 24×20

= 480cm²

no. of times area of the New rectangle is more than original rectangle = 480/120

= 4

hence 4 times the area of new rectangle is more than the area of the original rectangle.

hope this helps..!