Question

length of a rectangle is 16 cm and diagonal is 20 cm find its breadth​

Answer 1

Answer:

Length=16 cm=base

Diagonal=20 cm=hypotenuse

Breadth=perpendicular

one of the triangle formed due to diagonal,

using Pythagoras,

h^2={16^2+b^2}

400=256+b^2

√144=b

b=12 cm

Answer 2

Step-by-step explanation:

l=,16 cm,diagonal is 20

In rectangle ABCD, BD is the diagonal

in triangle ABC

right angle at A

Then AB=16cm

BD=20

using pythagoras theorem you can find the answer

(AB)^2+(AC)^2=(BD)^2