Question

length of a rectangle is 16 cm less than twice its breadth. if the perimeter of the rectangle is 100 cm, find its length and breadth.

Answer 1

breadth= X
length = x-16

now, 2(l+b) = 100
2[X+(x-16)] = 100
2(2x-16) =100
4x-64=100
4x=100+64
4x=164
X=164/4
X= 41cm = breadth
length = (41-16)= 25cm

Answer 2

Given :

Length of a rectangle is 16 cm less than twice its breadth. if the perimeter of the rectangle is 100 cm,

To find :

Find its length and breadth.

Solution :

Let the breadth of rectangle be "a" cm

∴ Length of rectangle = (2a - 16) cm

∵ Perimeter of rectangle = 2(length + breadth)

So atq,

⇒ 100 = 2(2a - 16 + a)

⇒ 100 = 2(3a - 16)

⇒ 100/2 = 3a - 16

⇒ 50 = 3a - 16

⇒ 50 + 16 = 3a

⇒ 66 = 3a

⇒ a = 66/3

⇒ a = 22 cm

∴ Breadth of rectangle = 22 cm

∴ Length of rectangle = 2a - 16 = 2(22) - 16 = 44 - 16 = 28 cm

Therefore,

Length and breadth of rectangle are 28 cm and 22 cm respectively.