Question

length of a rectangle is 16 m and length of diagonal is 20 meter. Find the perimeter of rectangle​

Answer 1

Given :

• Length of rectangle = 16 m
• Diagonal of rectangle = 20 m

To Find :

• The perimeter of rectangle = ?

Solution :

First of all we need to find the breadth of rectangle :

• Let breadth of rectangle be 'b'.

→ Diagonal = √(Length)² + (Breadth)²

→ 20 = √(16)² + b²

→ 20 = √256 + b²

Squaring both the sides we get :

→ 400 = 256 + b²

→ 400 - 256 = b²

→ 144 = b²

→ b² = 144

Taking square root to the both sides we get :

→ b = √144

→ b = 12 m

• Hence,the breadth of rectangle is 12 m.

★ Now,let's find the perimeter of rectangle :

→ Perimeter of rectangle = 2(Length + Breadth)

→ Perimeter of rectangle = 2(16 + 12)

→ Perimeter of rectangle = 2 × 28

→ Perimeter of rectangle = 56 m

• Hence,the perimeter of rectangle is 56 m.

Extra Formuals :-

• Volume of cylinder = πr²h
• T.S.A of cylinder = 2πrh + 2πr²
• Volume of cone = ⅓ πr²h
• C.S.A of cone = πrl
• T.S.A of cone = πrl + πr²
• Volume of cuboid = l × b × h
• C.S.A of cuboid = 2(l + b)h
• T.S.A of cuboid = 2(lb + bh + lh)
• C.S.A of cube = 4a²
• T.S.A of cube = 6a²
• Volume of cube = a³
• Volume of sphere = 4/3πr³
• Surface area of sphere = 4πr²
• Volume of hemisphere = ⅔ πr³
• C.S.A of hemisphere = 2πr²
• T.S.A of hemisphere = 3πr²

Answer 2

Answer:

56 m

Step-by-step explanation:

Let the rectangle be ABCD.

So in ∆ ABD(divided by the diagonal BD in rectangle ABCD), angle A= 90°

By Pythagoras Theorem,

AB^2+ AD^2= BD^2

16^2 + AD^2= 20^2

256+ AD^2= 400

AD= √400-256

AD= √144

AD= 12m

Perimeter of rectangle=2(l+b)= 2(16+12)= 2(28)= 56m.

Hope it helps