Length of a rectangle is 1cm more than its breadth. The diagonal is 29cm. Find the area of the rectangle
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let the breadth be xcm then length will be x+1cm.as this is a right Angeled ∆ .eq.

(by solving the eq. we get )
x=-21 & x= 20
as distance cannot be -ve.
so,x=20cm breadth is20cm & length is 21cm.
area of ∆is 1/2×b×h
so,1/2×20×21=210cm
(by solving the eq. we get )
x=-21 & x= 20
as distance cannot be -ve.
so,x=20cm breadth is20cm & length is 21cm.
area of ∆is 1/2×b×h
so,1/2×20×21=210cm
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