Math, asked by nainachhoker31, 4 months ago

length of a rectangle is 2.5 times its bredth. if its perimeter is 56m then its area (in sq.m) is​

Answers

Answered by sarvikab2003
0

Answer:

let breadth be 'b' m

so, length=2.5b=l

now, perimeter of a rectangle is= 2(l+b)

so here,

56=2(l+b)

28=(2.5b+b)

28=3.5b

8m=b

now area of rect.

= l×b= (2.5×8)×8

=160 m^2

ohaiyo!

Answered by harryinformz
0

Answer:

area = 160 sq.m

Step-by-step explanation:

let's

the breadth of a rectangle = x

then , according to question

length of rectangle = 2.5 x

perimeter of rectangle = 2 ( length + breadth)

56 = 2 ( 2.5x + x )

56 = 2 ( 3.5x)

56 = 7.0x

56 ÷ 7 = x

x = 8

so, breadth of rectangle = 8m

and length = 2.5 × 8

= 20.0m

then ,

area of rectangle = length × breadth

= 20.0m × 8m

= 160.0 m²

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