Question

length of a rectangle is 27 M longer than its breadth if the perimeter of rectangle is 110 M then find its area

Answer 1

$\bf\huge\boxed{\boxed{\boxed{Cybary\:Radhe\:Radhe}}}$

Length = Breadth + 27

Length = b

Perimeter =2(l + b)

110  = 2(2b + 27)

110 = 4b + 54

110 - 54 = 4b

56 = 4b

b = 14cm  

Area of Rectangle = l × b

Length = 27 + 14

= 41

Area = 14 × 41

= 574$\bf\huge cm^{2}$

$\bf\huge\boxed{\boxed{\boxed{Radhe\:Radhe}}}$

Answer 2

$\huge \bf{hey}$

$\huge{ \mathfrak{here \: is \: answer}}$

$\bf{given \: - }$
$\sf{length = 27m}$
$\sf{perimeter = 110m}$
$\sf{to \: find = \: breadth \: and \: area}$

$\sf{let \: the \: breadth \: of \: rectangle \: be \: x}$

$\sf{perimeter \: = 2(l + b)}$

$\sf{2(27 + 2x) = 110}$

$\sf{54 + 4x = 110}$

$\sf{4x = 110 - 54}$

$\sf{4x = 56}$

$\sf{x = \frac{56}{4}}$

$\bf{x = 14}$
$\bf{hence \: breadth = 14m}$

$\huge{now - \: area}$

$\bf{area = length \times \: breadth}$

now
length= 27+14=41

$\sf{41 \times\: 14}$

$\bf{574 \: m }^{2}$
$\huge \boxed{ \boxed{ \boxed{hope \: it \: helps}}}$
$\huge{ \mathbb{THANKS}}$