length of a rectangle is 3 more than its breadth and its area is 154 cm2 express this in a from of a suitable quadratic equation
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Answered by
4
Let the breadth be x and length be y
y = x + 3
Area of rectangle = length * breadth = x * y ( substituting y = x +3 here )
x * (x+3) = 154 cm²
x(x+3) = x² + 3x =154
x² +3x - 154 = 0
Hope it helps!!
Cheers!!
y = x + 3
Area of rectangle = length * breadth = x * y ( substituting y = x +3 here )
x * (x+3) = 154 cm²
x(x+3) = x² + 3x =154
x² +3x - 154 = 0
Hope it helps!!
Cheers!!
Answered by
1
length=breadth+3⇒l=b+3
Area, A=154cm²
A=l×b
⇒154=(b+3)×b
⇒b²+3b=154
⇒b²+3b-154=0
(it is in the form of a quadratic equation, ax²+bx+c=0,where a=1,b=3,c= -154)
Area, A=154cm²
A=l×b
⇒154=(b+3)×b
⇒b²+3b=154
⇒b²+3b-154=0
(it is in the form of a quadratic equation, ax²+bx+c=0,where a=1,b=3,c= -154)
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