Question

length of a rectangle is 5 cm more than twice of its breadth if area of the rectangle is 1950 square cm then find the perimeter of rectangle ​

Answer 1

Answer:

ANS 190

Step-by-step explanation:

PLZZ MARK AS BRAINLIEST

Answer 2

Answer:

Let the breadth of the rectangle be 'x' and that of length be 'y'.

According to the given condition,

→ y = 2x + 5

Also it is given that the area of the rectangle is 1950 cm².

→ Area of rectangle = length × breadth

→ Area = ( 2x + 5 ) ( x ) = 1950 cm²

→ 2x² + 5x = 1950

→ 2x² + 5x - 1950 = 0

→ 2x² + 65x - 60x - 1950 = 0

→ x ( 2x + 65 ) - 30 ( 2x + 65 ) = 0

→ ( x - 30 ) ( 2x + 65 ) = 0

→ x = -32.5, 30

Hence the breadth of the rectangle is 30 cm as length cannot be negative.

Therefore length is equal to:

→ 2 ( 30 ) + 5

→ 60 + 5

→ 65 cm

Therefore Perimeter of a rectangle = 2 ( l + b )

→ 2 ( 30 + 65 )

→ 2 ( 95 )

→ 190 cm

Therefore the perimeter of the rectangle is 190 cm.