Question

length of a rectangle is 5 metre less than twice its breadth if the perimeter of the rectangle is 52 find the length and breadth?​

Answer 1

$\sf \bold{Given : }$

• Length of a rectangle is 5 m less than its breadth .

• Perimeter of the rectangle is 52 m.

$\sf \bold{To \: find \: out : }$

Find the length and breadth?

$\sf \bold{Formula \: used : }$

★Perimeter of rectangle = 2 ( Length + Breadth )

$\sf \bold{Solution : }$

Let the breadth be x .

Then, length = 2x - 5

★According to question:-

Perimeter of rectangle = 2 ( Length + Breadth)

Substituting the values

→ 52 = 2 ( 2x - 5 + x )

→ 52 = 2 ( 3x - 5 )

→ 3x - 5 = 52/2

→ 3x - 5 = 26

→ 3x = 26 + 5

→ 3x = 31

→ x = 31/3

✪Length = 2x - 5 = 2 × 31/3 - 5 = 62/3 - 5 = 47/3

✪Breadth = x = 31/3

Answer 2

Answer: length of a rectangle is 5 metre less than twice its breadth . Perimeter = 52 m

To find : the length and breadth

Solution:

Let say Length & Breadth of rectangle are

L & B m

L = 2B -  5

Perimeter = 2 ( L + B )

Perimeter = 52

=> 2(L + B)  = 52

=> L + B= 26

=> L = 26 - B

Equating L from both equations  

2B - 5 = 26 - B

=> 3B = 31

=> B = 31/3

L = 26 - 31/3

=> L = (78 - 31)/3

=> L = 47/3

Hence length of Rectangle = 47/3  m & Breadth = 31/3 m

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