Question

Length of a rectangle is 5 more than twice of its breadth. The perimeter of the rectangle is 100 cm. The area of the rectangle?​

Answer 1

Answer:

625sq.cm

Step-by-step explanation:

Its the answer

Answer 2

$\Large {\textsf{\textbf \red{ツ~~~Question :-}}}$

» Length of a rectangle is 5 more than twice of its breadth. The perimeter of the rectangle is 100 cm. The area of the rectangle?

$\Large {\textsf{\textbf \green{ツ~~~Solution :-}}}$

• To find the area of the rectangle, we will have to first find the accurate length & breadth of the rectangle. For this, we have to change the statement to linear equation. . .

$ \leadsto $ Here, the Equation recieved will be;

$ \tt{Perimeter = 2(l + b)}$

$ \mapsto \tt{100 = 2(2x + 5 + x)}$

$ \mapsto \tt{100 = 2(2x + x + 5)}$

$ \mapsto \tt{100 = 2(3x + 5)}$

$ \mapsto \tt{100 = 6x+ 10}$

$ \mapsto \tt{6x+10=100}$

$ \mapsto \tt{6x=100-10 }$

$ \mapsto \tt{6x=90 }$

$ \mapsto \tt{x=\frac{90}{6} }$

$ \mapsto \bf \red{x = 15}$

• Here, if the the breadth of the rectangle is 15 cm, the length of the rectangle will be;

$ \tt{Length = 2x + 5}$

$ \mapsto \tt{Length = 2(15)+5}$

$ \mapsto \tt{Length = 30 + 5}$

$ \mapsto \bf \red{Length = 35}$

• Now, we found the length to be 35 cm.

_Next,

• We have to find out the area of the rectangle;

$ \tt{Area ~of ~Rectangle = (Length \times Breadth)}$

$ \mapsto \tt{Area = (15 cm \times 35 cm)}$

$ \mapsto \bf \red{Area = 525 cm^{2}}$

• Hence, the area of the rectangle will be 525 cm².

— ItZzVaibhu —