Question

length of a rectangle is 5cm more than twice of its breadth of area of the rectangle is 1950sq.cm then find the perimeter of rectangle​

Answer 1

Answer:

5*2x=1950

x=1950/10

=195

p=2(5+195)

=400

Answer 2

❏ Using ForMuLaS

 ❍For a rectangle:-    

 •Area=(length×Breadth)              

•Perimeter=2(length+Breadth)

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❏ Solution  

$Given \begin{cases}</p><p>\sf{length\: is\: 5cm \:more \:than\: twice\: of\: its \:breadth}\\</p><p>\sf{Area=1920}\:cm{}^{2}</p><p>\end{cases}$

Let, the breadth of the rectangle is =X cm

Now, given that length of a rectangle is 5cm more than twice of its breadth ,

∴Length=(2X+5) cm

 Now , Area of the rectangle is =1950 cm²  

∴ length×breadth=Area

➾(2X+5)×X=1950

➾2X²+5X=1950

➾2X²+5X-1950=0

➾2X²+65X-60X-1950=0

➾X(2X+65)-60(X+65)=0

➾(2X+65)(X-60)=0

Either,  2X+65=0

➾X=$\sf\frac{-65}{2}$   (as, length can't be Negative so it's cancelled or not taken into consideration)

Or

X-60=0

➾X=60  ∴Length=(2×60+5)cm=125 cm

∴Length=(2×60+5)cm=125 cm∴Breadth=60 cm

so, perimeter of the Rectangle is

=2×[125+60] cm

=(2×185) cm

=370 cm

∴$\boxed{perimeter=370\: cm.}$

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$\underline{ \huge\mathfrak{hope \: this \: helps \: you}}$  

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