Question

length of a rectangle is 6M less than twice its breadth if its perimeter is 66m find its length and breadth

Answer 1

Let the breadth of the rectangle be b therefore its length is 2b minus 6 and according to the question perimeter of rectangle 148 metre therefore
2(length+breadth)=66
2(2b-6+b)=66
2(3b-6)=66
3b-6=33
then b= 39/3=13m and length equals to 26 minus 6 equal to 20 answer

Answer 2

HEY THERE!!

Question;-

Length of a rectangle is 6M less than twice its breadth if its perimeter is 66m find its length and breadth.

Method Of Solution;

Let to be Required breadth x

According to the Question;

*length of a rectangle is 6M less than twice its breadth*

=> 2x-6

Given: Perimeter of Rectangle
= 66

We know that formula of Perimeter of Rectangle= 2(l+b)

Substitute Required terms in Formula

2(L+b) =Perimeter

=> 2(2x-6+x)=66

=> 2(3x-6)=66

=> 3x-6=66/2

=> 3x-6=33

=> 3x=33+6

=> x=39/3


•°• x=13

Here, X is Equal as Breadth of Rectangle= 39 metre

Again, To find Length of Rectangle=?

Length =2x-6

Substitute the value of x in length to find it.

Length =2x-6
=2(13)-6
=26-6
=20

Hence,

Length of Rectangle=20 metre

Breadth of Rectangle=13 metre