Question

length of a rectangle is 7 cm more than its breadth. if the area of the rectangle is 60 sq cm, determine the dimensions of a rectangle​

Answer 1

Let breadth be x

Let Length be x+7

Area Given : 60 cm²

x(x+7)=60

x²+7x-60=0

x²+12x-5x-60=0

x(x+12)-5(x+12)=0

(x+12)(x-5)=0

x = -12,5 [Since Length and Breadth Cannot be negative so x = 5]

Length = x+7 = 12

Breadth = x = 5

Answer 2

Given : length is 7 cm more than its breadth

area of rectangle is 60 sq cm.

To find: dimensions of a rectangle​

Step-by-step explanation:

According to question

Let the breadth be x cm

and the length is 7 more than its breadth = x+7

Now applying the formula area of rectangle = $length \times breadth$

Area of rectangle = $length \times breadth$

$60=(7+x)(x)$

$60=7x+x^2$

$x^2+7x-60$

Using middle term splitting

$x^2+12x-5x-60$

$x(x+12)-5(x+12)$

$(x+12)(x-5)$

$x=-12$ and $x=5$

Length should not be -ve so the value of x = 5

breadth  =  5 cm and

length =  5+7 = 12 cm