Question

length of a rectangle is 8cm less the twice it breadth if the parameters of rectangle is 56mts find its length and breadth​

Answer 1

Answer:

see this is the answer

Step-by-step explanation:

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Answer 2

Solution:

Let length be x and breadth be y

•°•By first condition,

$x = 2y - 8$

Now we have perimeter of rectangle =56m=5600cm

•°• By second condition,

$2(x + y) = 5600$

By putting value of x in second condition by substitution method

$2(x + y) = 5600 \\ 2((2y - 8) + y) = 5600 \\ 2(y - 8) = 5600 \\ (y - 8) = \frac{5600}{2} \\ (y - 8) = 2800 \\ y = 2800 + 8 \\ y = 2808$

$x = 2y - 8 \\ x = 2(2808) - 8 \\ x = 5616 - 8 \\ x = 5608$

There Length will be 5608cm that is 56.08m and Breadth will be 2808cm that is 28.08m

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