Question

Length of a rectangle is 8m less than twice its breadth.If the perimeter of the rectangle is 56m,find its length and breadth ​

Answer 1

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GiveN:

• Length of a rectangle is 8m less than twice its breadth.
• Perimeter of the rectangle is 56 m

To Find:

• Length and breadth of the rectangle...?

Step-wise-Step Explanation:

According to Question, the length may be greater or less than the breadth. For convenience, let the breadth be x.

⇒ Length = 2(Breadth) - 8

⇒ Length = 2x - 8

Now we can find the perimeter of the rectangle by using the formula. But the perimeter given is 56 m.

• Perimeter = 2(Length + Breadth)

Putting the values of length and breadth,

⇒ P = 2(l + b)

⇒ 56 = 2(2x - 8 + x)

⇒ 56 = 2(3x - 8)

⇒ 3x - 8 = 28 m

⇒ 3x = 36 m

⇒ x = 12 m

Then the length and breadth of the rectangle:

• Length = 2x - 8 = 16 m
• Breadth = 12 m

And we are done!

Answer 2

Question

Length of a rectangle is 8m less than twice its breadth. If the perimeter of the rectangle is 56m, find its length and breadth.

Solution

Perimeter = 56m

Let, breadth be x

length be 2x-8

ATP

$2(2x - 8 + x) = 56 \\ = ) \: 2(3x - 8) = 56 \\ = ) \: 6x - 16 = 56 \\ = ) \: 6x = 56 + 16 \\ = ) \: 6x = 72 \\ = ) \: x = \frac{72}{6} = 12$

Ans:- Length = (24-8)m = 16m

Breadth = 12m