Question

LENGTH OF A RECTANGLE IS 8M LESS THAN TWICE ITS BREATH IF THE PERIMETER OF THE RECTANGLE IS 56 METERS FIND OTS LENGTH AND BREADTH

Answer 1

Answer:

The length is 16 m and breadth is 12 m.

Step-by-step explanation:

Given :

Perimeter = 56 m

Length = 8 m more than breadth

To find :

The length and breadth

Solution :

Let the -

• Breadth be y
• Length be (2y - 8)

★ Perimeter = 2(Length + Breadth)

⇒ 2(2y - 8 + y) = 56

⇒ 2(3y - 8) = 56

⇒ 6y - 16 = 56

⇒ 6y = 56 + 16

⇒ 6y = 72

⇒ y = 72/6

⇒ y = 12

Breadth = 12 m

$\rule{300}{1.5}$

★ Length =

⇒ 12 + 8

⇒ 16 m

Length = 18 m

Therefore, the length is 16 m and breadth is 12 m.

Answer 2

Answer:

$\large\boxed{\sf{Length=16\;m}}$

$\large\boxed{\sf{Breadth=12\;m}}$

Step-by-step explanation:

Let the required Breadth of rectangle be 'b'

Therefore, according to question,

Length of rectangle = (2b-8)

Also, it's given that

Perimeter od rectangle = 56 m

But, we know that,

Perimeter of a rectangle is given by the formula, 2 (length + breadth)

Therefore, we will get,

$= > 2(2b - 8 + b) = 56 \\ \\ = > 2(3b - 8) = 56 \\ \\ = > 3b - 8 = \dfrac{56}{2} \\ \\ = > 3b - 8 = 28 \\ \\ = > 3b = 28 + 8 \\ \\ = > 3b = 36 \\ \\ = > b = \dfrac{36}{3} \\ \\ = > b = 12$

Thus, we get,

Breadth of rectangle = 12 m

Length of rectangle = (2×12 - 8) = 16 m

Hence, the Length and Breadth of the rectangle are 16 m and 12 m respectively.