Question

length of a rectangle is 8m less then twice its breadth if the primeter rectangle is 56 m find its length and breadth ​

Answer 1

Step-by-step explanation:

Let th length be l and breadth be b.

ATQ, -l+2b=8 ---(1)

Perimeter =2(l+b) -

2(l+b)=56

So, l+b=28 --(2)

Solving (1) and (2) by elimination method, we have -

l = 16 m

b = 12 m

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