Question

length of a rectangle is 8meters less than twice its breadth. if the perimeter of the rectangle is 56cm find its length and breadth.


please tell me the answer with explanation​

Answer 1

Answer:

Let length and breadth the field are l and b respectively. Then,

l=2b−8⇒2b=8+l⟶(1)

The perimeter of the rectangular field =56 m

⇒2(l+b)=56m⇒2l+2b=56m

from (1), we get

2l+8+l=56⇒3l=48⇒l=16m

∴ Length of rectangular field =16m

Breadth of rectangular field =

2

16+8

=12m

Answer 2

Answer:

let breadth = x

the length =2x-8

given perimeter = 56 cm

perimeter = 2(l+b)

= 2(2x-8+x)

56/2=3x-8

28=3x-8

36=3x

x=12