length of a rectangle is four times its breadth. if length and breadth both increased by 3cm ,the area of new rectangle will be 84 sq.cm more than the area of given rectangle. find the length and breadth of given rectangle
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Let length = x and breadth = y
x = 4y ---------------eq1
Length and breadth increased by 3
x + 3 = y + 3
(x + 3)(y +3) = ( x × 4y) + 84
xy + 3x + 3y + 9 = 4xy + 84
3x + 3y + 9 = 3xy + 84
Taking common from both side...
3 (x + y + 3) = 3 (xy + 28)
x + y + 3 = xy + 28
Put x = 4y from eq1
4y + y + 3 = 4y ×y + 28
Now solve this equation u will get y and then put y in eq 1 u will get x.
x = 4y ---------------eq1
Length and breadth increased by 3
x + 3 = y + 3
(x + 3)(y +3) = ( x × 4y) + 84
xy + 3x + 3y + 9 = 4xy + 84
3x + 3y + 9 = 3xy + 84
Taking common from both side...
3 (x + y + 3) = 3 (xy + 28)
x + y + 3 = xy + 28
Put x = 4y from eq1
4y + y + 3 = 4y ×y + 28
Now solve this equation u will get y and then put y in eq 1 u will get x.
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