Math, asked by bhupinderkaur60221, 4 months ago

Length of a rectangle is three times its breadth. Perimeter of the rectangle is 40 cm. Find its
length and width.


uditpanigrahi13: Let l and b be the length and breadth of rectangle

Given that, l=3b

We know that,

Perimeter of the rectangle =2×(l+b)

⇒40 cm=2×(3b+b)=2×4 b=8 b

⇒b=840​cm=5 cm

⇒l=3b=3×5 cm=15 cm.

Hence, the length and width of the rectangle are 15 cm and 5 cm% respectively.
uditpanigrahi13: answer

Answers

Answered by rainasaini0001
2

Answer:

x = 3.64

Step-by-step explanation:

let the length be = 3x

let the breadth be = x

perimeter of rectangle = l × b

40cm = 3x × x

40cm = 3x^2

40 / 3 = x^2

13.3 = x^2

_/ 13.3 = x

3.64... = x

x = 3.64

Answered by Anonymous
12

 \mathfrak{ \large{ \pink{ \underline{ \orange{Correct  \: Question: }}}}}

Length of a rectangle is three times its breadth. Perimeter of the rectangle is 40 cm. Find its length and width.

 \mathfrak{ \large{ \pink{ \underline{ \orange{ Given:  }}}}}

  • Perimeter of rectangle = 40 cm
  • Length is three times the breadth of rectangle

 \mathfrak{ \large{ \pink{ \underline{ \orange{ To  \: Find :  }}}}}

  • Length and breadth of rectangle

 \mathfrak{ \large{ \pink{ \underline{ \orange{ Solution: }}}}}

  • Let the breadth of rectangle be x
  • The length of rectangle will be 3x

\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\ \mathfrak { \underline{ \green{Formula\: to\: calculate\: perimeter\: of\: rectangle}}}

 \boxed{ \boxed{ \mathfrak{ \large{ \red{perimeter = 2(length + breadth)}}}}}

According to question,

 \large{ \sf \longmapsto \:  \:  \:  \:  \:  \:  \:  \:  \: 2(x + 3x) = 40}

 \large{ \sf \longmapsto \:  \:  \:  \:  \:  \:  \:  \:  \:2(4x) = 40}

 \large{ \sf \longmapsto \:  \:  \:  \:  \:  \:  \:  \:  \:4x =  \frac{40}{2} } \\

 \large{ \sf \longmapsto \:  \:  \:  \:  \:  \:  \:  \:  \:4x = 20}

 \large{ \sf \longmapsto \:  \:  \:  \:  \:  \:  \:  \:  \:x =   \cancel\frac{20}{4} } \\

 \large{ \sf \longmapsto \:  \:  \:  \:  \:  \:  \:  \:  \boxed{ \purple{ \underline{ \mathfrak{x = 5}}}}}

Now,

  • Length of rectangle = 3x = 15 cm
  • Breadth of rectangle = x = 5 cm

 \mathfrak{ \large{ \pink{ \underline{ \orange{ Hence: }}}}}

The length and breadth of rectangle are 15 cm and 5 cm.


Cordelia: amazing ans ❤️❤️
Sen0rita: thanku ❤️ :D
Cordelia: tumhara ans h ni waise xD
Anonymous: Thanku ❣️@Cordelia
Sen0rita: xD thanku dene me kya jaa raha xD
Anonymous: hann hann xD
Sen0rita: XD XD
Cordelia: ye bhi theek h xD
Sen0rita: XD XD
Anonymous: XD
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