Question

Length of a rectangular field is three with more than twice its breadth then express the area of reactangle in the form of polynomial

Answer 1

$\mathbb{ SOLUTION }$:

Let, the breadth of the rectangle be $\bf{b}$ units

According to the question,
The length of the rectangle is 3 more than twice of its breadth.
So,
length = (2 $\bf{b}$ + 3) units

Area of the rectangle = (length × breadth) unit square

Area = (2 $\bf{b}$ + 3) × $\bf{b}$ unit square

Area = ( 2 $\bf{b}$² + 3 ) unit square

Answer 2

$\underline{\bold{Given:-}}$

The length of a rectangular field is 3 more than twice its breadth.

$\underline{\bold{To\:find:-}}$

Area of the rectangle in the form of a polynomial.

$\underline{\bold{Solution:-}}$

Let, the breadth of the rectangle be b unit.

Length = (2b+3) unit

Area of rectangle = length × breadth

$= (2b + 3) \times b \\ \\ \boxed{Area\: of\: rectangle=(2 {b}^{2} + 3b) \: {unit}^{2} }$

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