Length of a rectangular is increased by 20 % and breadth is decreased by 10% then perimeter is
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Let the Initial Length of rectangle be L and Breadth be B
Let the new Length of rectangle be L' and Breadth be B'
Let Initial Perimeter be P and New Perimeter be P'
According to the question, New length is 20% more than the initial length
Thus,
L' = L + 20% of L
L' = L + 0.20 L
L' = 1.2 L
and also new breadth is 10% less than the initial breadth,
So, B' = B - 10% of B
B' = B - 0.1 B
B' = 0.9 B
Now the perimeter can be calculated as,
P' = 2 (L' + B')
P' = 2 (1.2 L + 0.9 B)
P' = 2.4 L + 1.8 B
This way we can calculate the new perimeter
Let the new Length of rectangle be L' and Breadth be B'
Let Initial Perimeter be P and New Perimeter be P'
According to the question, New length is 20% more than the initial length
Thus,
L' = L + 20% of L
L' = L + 0.20 L
L' = 1.2 L
and also new breadth is 10% less than the initial breadth,
So, B' = B - 10% of B
B' = B - 0.1 B
B' = 0.9 B
Now the perimeter can be calculated as,
P' = 2 (L' + B')
P' = 2 (1.2 L + 0.9 B)
P' = 2.4 L + 1.8 B
This way we can calculate the new perimeter
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