Question

length of a rectangular Park is 250 and with is 150 Anu runs Around The Park 3 times what is the total distance covered by her in km. let's check your brain. who will give the right answer, I will make them brainliest. ​

Answer 1

Step-by-step explanation:

perimeter=2(250+150)

=800m

3 times

distance=3*800=2400m

= 2.4km

Answer 2

Given:-

• Length of the rectangular park = 250 m
• Breadth = 150 m

To Find:-

The total distance covered by her around the park 3 times in km?

Solution:-

Given that,

$l$ = 250m

To find the solution in km, we first have to convert the length and breadth into km.

So,

To convert in km, simply divide it by 1000

250/1000

➩ 0.25 km

And,

b = 150/1000

➩ 0.15 km

So,

$\mapsto\sf Distance \: covered \: by \: Anu= perimeter \: of \: park × 3$

$\sf= 2(l+b)×3$

$\sf=2(0.25+0.15)×3$

$\: \: \sf=6×0.4$

$\sf =2.4 \: km$

Diagram of the rectangular park:-

$\: \: \: \: \: \: \: \: \: \: \: \sf250 \: m \\ \begin{gathered}\begin{gathered}\begin{gathered} \sf150 \: m \: \: \: \: \boxed{\begin{array}{c}\sf \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \end{array}}\end{gathered}\end{gathered}\end{gathered} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf @Fairydust$

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Additional Information:-

$\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin{array}{c}\sf Area~ of ~a ~square~ = ~side × side~ (side)² \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:  \:  \:  \:  \:   \\ \\ {\sf Area \:  of ~a ~rectangle~ = length~ × ~breadth \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }  \\ \\ {\sf Area~ of ~a ~circle~ = ~πr² \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: }  \\ \\ {\sf Area~of~a~triangle~ =  \dfrac{1}{2}  × b× h \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \:  \:  \:  \:  } \\  \\ {\sf Surface ~area ~ of~a~cylinder~=~2π ×~r×h \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: } \\ \\{\sf Surface~area~of~a~sphere~=~4πr² \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: } \: \end{array}}\end{gathered}\end{gathered}\end{gathered}$