length of a room is one and a half time of its breadth. the cost of carpeting the room at rs. 325 per m2 is rs. 17550 and the cost of carpeting the walls at rs. 140 per m2 is rs. 24080. Find the dimensions of the room.
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solution :-
Let the breadth of the room be b .
Then, length of the room l = 1.5 b
Area carpeted by Rs 3.25 = 1m²
area carpeted with Rs 175.50 is the area of the floor.
the area of the floor = 1 / 3.25 × 175.50 = 54 m²
therefore lb=54
(1.5b) × b=54
1.5b²= 54
b² = 54/ 1.5 = 36
b = 6m.
therefore, the breadth of the room is 6 m.
length of the room =1.5× 6= 9 m
let the height of the room be h m.
area of the walls = 2h ( l + b ) = 2h ( 9+6) = 30hm²
since 1 door and 2 windows occupy 8 meter square.
therefore area of papering =30h-8 meter square......(1)
cost of papering the walls at Rs. 1.40 per m2 is Rs. 240.80.
therefore area of papering = 240.80/ 1.40 = 172m²
Now, from the eqn 1 ...........
30h - 8 = 172
30h = 180
h= 180/ 30
= 6m.
therefore, the height of the room is 6 m.
hence the dimensions of the room is 9× 6 ×6.
Let the breadth of the room be b .
Then, length of the room l = 1.5 b
Area carpeted by Rs 3.25 = 1m²
area carpeted with Rs 175.50 is the area of the floor.
the area of the floor = 1 / 3.25 × 175.50 = 54 m²
therefore lb=54
(1.5b) × b=54
1.5b²= 54
b² = 54/ 1.5 = 36
b = 6m.
therefore, the breadth of the room is 6 m.
length of the room =1.5× 6= 9 m
let the height of the room be h m.
area of the walls = 2h ( l + b ) = 2h ( 9+6) = 30hm²
since 1 door and 2 windows occupy 8 meter square.
therefore area of papering =30h-8 meter square......(1)
cost of papering the walls at Rs. 1.40 per m2 is Rs. 240.80.
therefore area of papering = 240.80/ 1.40 = 172m²
Now, from the eqn 1 ...........
30h - 8 = 172
30h = 180
h= 180/ 30
= 6m.
therefore, the height of the room is 6 m.
hence the dimensions of the room is 9× 6 ×6.
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