Math, asked by krithikaks7437, 1 year ago

Length of a room is one and a half times of its breadth the cost of carpeting the room at rupees 3.25 per metre square is rupees 175. 50 and the cost of papering the walls at 1.40 per metre square is rupees 240. 8081 door and to windows occupy 8 m square find the dimensions of the room

Answers

Answered by navadeep7
53
Solution :-

Let the breadth of the room be b .

Then, length of the room l = 1.5 b

Area carpeted by Rs 3.25 = 1m²

area carpeted with Rs 175.50 is the area of the floor.

the area of the floor = 1 / 3.25 × 175.50 = 54 m²

therefore lb=54

(1.5b) × b=54

1.5b²= 54

b² = 54/ 1.5 = 36

b = 6m.

therefore, the breadth of the room is 6 m.

length of the room =1.5× 6= 9 m

let the height of the room be h m.

area of the walls = 2h ( l + b ) = 2h ( 9+6) = 30hm²

since 1 door and 2 windows occupy 8 meter square.

therefore area of papering =30h-8 meter square......(1)

cost of papering the walls at Rs. 1.40 per m2 is Rs. 240.80.

therefore area of papering = 240.80/ 1.40 = 172m²

Now, from the eqn 1 ...........

30h - 8 = 172

30h = 180

h= 180/ 30

= 6m.

Hope it helps you
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Answered by rithikha13
13

Step-by-step explanation:

this is the answer givn in rd sharma bk

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