Question

length of a shadow of a 15 metres high pole is 5root by 3 metres at 7'0 clock in the morning then what is the angle of elevation of the sun rays with the ground at the time​

Answer 1

Length of pole is XY = 15m.

$\sf Shadow \: of \: pole \: is  = YZ = 5 \sqrt{3}$

angle of elevation of sun with ground is ∅ as shown in figure.

( in image )

Here in a right angled triangle,

$\tan (90°-∅)=\frac{YZ}{XY} = \frac{5\sqrt{3} }{15}=\frac{1}{\sqrt{3} }$

$\implies \tan (90°-∅)=\frac{1}{\sqrt{3} } \\ \implies 90°-∅=60° \\ \implies ∅=30°$

${ \boxed{ \sf \blue{{ \underline{Hence, Elevation \: is \to }}{ \boxed{ \red{30°}}}}}}$