Question

length of a shadow of a 15m high pole is
$5 \sqrt{3}$
meters at 7o'clock in the morning.then what is the angle of elevation of the sun rays with the ground at the time ​

Answer 1

Answer:

the angle is 60°.

Step-by-step explanation:

height of the pole= 15m

length of shadow= 5√3m

we know tanθ = perpendicular/base

= 15/5√3

= √3

if tanθ= √3

i.e. θ= 60°