length of a steel pipe is 2.1m and radius is 8cm. calculate the surface area if pipe is open at the both ends
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A water drop is observed to fall
through a fluid of density 1 kg/m³
with a constant velocity of 9.8 m/s.
What is the radius of the drop? Take
the coefficient of viscosity of fluid as
0.000002 .
The radius of the water drop will be,
r^2 = v x n x 9/rhogx2
=>r^2= 9.8 x 0.000002x9/1x9.8x2
=>r^2=0.000009
=>r= 3X10^-4 m
Radius of the droplet is 3X10^-4 m
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