Question

Length of a tangent segment drawn froma point which is at a distance of 12.5 cm from the centre of a circle is 12 cm, find the diameter of the circle.​

Answer 1

ANSWER

Let external point be B. OA be radius of circle.

Let external point be B. OA be radius of circle. Given:

Let external point be B. OA be radius of circle. Given: OB=12.5 cm

Let external point be B. OA be radius of circle. Given: OB=12.5 cmAB=12 cm

Let external point be B. OA be radius of circle. Given: OB=12.5 cmAB=12 cmIn right triangle, AOB, by Pythagoras Theorem,

Let external point be B. OA be radius of circle. Given: OB=12.5 cmAB=12 cmIn right triangle, AOB, by Pythagoras Theorem,OB

Let external point be B. OA be radius of circle. Given: OB=12.5 cmAB=12 cmIn right triangle, AOB, by Pythagoras Theorem,OB 2

Let external point be B. OA be radius of circle. Given: OB=12.5 cmAB=12 cmIn right triangle, AOB, by Pythagoras Theorem,OB 2 =AB

Let external point be B. OA be radius of circle. Given: OB=12.5 cmAB=12 cmIn right triangle, AOB, by Pythagoras Theorem,OB 2 =AB 2

Let external point be B. OA be radius of circle. Given: OB=12.5 cmAB=12 cmIn right triangle, AOB, by Pythagoras Theorem,OB 2 =AB 2 +OA

Let external point be B. OA be radius of circle. Given: OB=12.5 cmAB=12 cmIn right triangle, AOB, by Pythagoras Theorem,OB 2 =AB 2 +OA 2

Let external point be B. OA be radius of circle. Given: OB=12.5 cmAB=12 cmIn right triangle, AOB, by Pythagoras Theorem,OB 2 =AB 2 +OA 2

Let external point be B. OA be radius of circle. Given: OB=12.5 cmAB=12 cmIn right triangle, AOB, by Pythagoras Theorem,OB 2 =AB 2 +OA 2 AO

Let external point be B. OA be radius of circle. Given: OB=12.5 cmAB=12 cmIn right triangle, AOB, by Pythagoras Theorem,OB 2 =AB 2 +OA 2 AO 2

Let external point be B. OA be radius of circle. Given: OB=12.5 cmAB=12 cmIn right triangle, AOB, by Pythagoras Theorem,OB 2 =AB 2 +OA 2 AO 2 =OB

Let external point be B. OA be radius of circle. Given: OB=12.5 cmAB=12 cmIn right triangle, AOB, by Pythagoras Theorem,OB 2 =AB 2 +OA 2 AO 2 =OB 2

Let external point be B. OA be radius of circle. Given: OB=12.5 cmAB=12 cmIn right triangle, AOB, by Pythagoras Theorem,OB 2 =AB 2 +OA 2 AO 2 =OB 2 −OA

Let external point be B. OA be radius of circle. Given: OB=12.5 cmAB=12 cmIn right triangle, AOB, by Pythagoras Theorem,OB 2 =AB 2 +OA 2 AO 2 =OB 2 −OA 2

Let external point be B. OA be radius of circle. Given: OB=12.5 cmAB=12 cmIn right triangle, AOB, by Pythagoras Theorem,OB 2 =AB 2 +OA 2 AO 2 =OB 2 −OA 2 =12.5

Let external point be B. OA be radius of circle. Given: OB=12.5 cmAB=12 cmIn right triangle, AOB, by Pythagoras Theorem,OB 2 =AB 2 +OA 2 AO 2 =OB 2 −OA 2 =12.5 2

Let external point be B. OA be radius of circle. Given: OB=12.5 cmAB=12 cmIn right triangle, AOB, by Pythagoras Theorem,OB 2 =AB 2 +OA 2 AO 2 =OB 2 −OA 2 =12.5 2 −12

Let external point be B. OA be radius of circle. Given: OB=12.5 cmAB=12 cmIn right triangle, AOB, by Pythagoras Theorem,OB 2 =AB 2 +OA 2 AO 2 =OB 2 −OA 2 =12.5 2 −12 2

Let external point be B. OA be radius of circle. Given: OB=12.5 cmAB=12 cmIn right triangle, AOB, by Pythagoras Theorem,OB 2 =AB 2 +OA 2 AO 2 =OB 2 −OA 2 =12.5 2 −12 2 =12.25

Let external point be B. OA be radius of circle. Given: OB=12.5 cmAB=12 cmIn right triangle, AOB, by Pythagoras Theorem,OB 2 =AB 2 +OA 2 AO 2 =OB 2 −OA 2 =12.5 2 −12 2 =12.25∴AO=3.5 cm

Let external point be B. OA be radius of circle. Given: OB=12.5 cmAB=12 cmIn right triangle, AOB, by Pythagoras Theorem,OB 2 =AB 2 +OA 2 AO 2 =OB 2 −OA 2 =12.5 2 −12 2 =12.25∴AO=3.5 cmDiameter=2(AO)=2(3.5)=7 cm