Question

length of a triangle is 8cm, its diagonal measures 10 m. Find its perimeter.

Answer 1

Answer:

Given

Length of the rectangle 10 m

Breadth of the rectangle =8 m

Hence, the perimeter of the rectangle is calculated as follows

Perimeter =2(Length+Breadth)

Perimeter =2(10 m+8 m)

=2×18 m

We get,

=36 m

Hence, the perimeter of the rectangle 36 m

Answer 2

Answer:

6 cm / 6 m

there is a typing error in the units.... if that is not the case then convert the centimetre into metre by dividing it by 100 or the vice versa by multiplying by 100

Step-by-step explanation:

Since a triangle does not have diagonals. thereafter I consider it a rectangle as the length and diagonal are given and we're supposed to find the perimeter.

since,

$d = \sqrt{ {l}^{2} + {b}^{2} }$

$d = \sqrt{ {l}^{2} + {b}^{2} } \\ \\ {d}^{2} = {l}^{2} + {b}^{2} \\ {b}^{2} = {d}^{2} - {l}^{2} \\ b = \sqrt{ {d}^{2} - {l}^{2} } \\ = \sqrt{ {10}^{2} - {8}^{2} } \\ = \sqrt{100 - 64 } \\ = \sqrt{36} \\ = 6$